6m^2+11m-95=0

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Solution for 6m^2+11m-95=0 equation:



6m^2+11m-95=0
a = 6; b = 11; c = -95;
Δ = b2-4ac
Δ = 112-4·6·(-95)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-49}{2*6}=\frac{-60}{12} =-5 $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+49}{2*6}=\frac{38}{12} =3+1/6 $

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